Embed Size px x x x x Solucionario analisis de circuitos en ingenieria 6ta edicion - j. View 2. All Rights Reserved. We require
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Embed Size px x x x x Solucionario analisis de circuitos en ingenieria 6ta edicion - j. View 2. All Rights Reserved. We require The mJ pulse lasts 20 ns. The 1-mJ pulse lasts 75 fs. Referring to Fig. Reading from the graph, this corresponds to approximately 3. Reading from the graph, this corresponds to roughly 0. The maximum power point, therefore, occurs somewhere between these two points. By trial and error, Pmax is roughly mV 2. Note that in the table below, only the 4-A source and the 3-A source are actually absorbing power; the remaining sources are supplying power to the circuit.
We will compute absorbed power by using the current flowing into the positive reference terminal of the appropriate voltage passive sign convention , and we will compute supplied power by using the current flowing out of the positive reference terminal of the appropriate voltage. We are asked to determine the voltage vs, which is identical to the voltage labeled v1.
The only remaining reference to v1 is in the expression for the current flowing through the dependent source, 5v1. This current is equal to i2. The battery delivers an energy of The supply voltage is V, and the maximum dissipated power is W. The fuses are specified in terms of current, so we need to determine the maximum current that can flow through the fuse. This exceeds the specified maximum power. If we choose the 4. This leads to a maximum power of 4.
Although W is less than the maximum power allowed, this fuse will provide adequate protection for the application circuitry. If a fault occurs and the application circuitry attempts to draw too much power, W for example, the fuse will blow, no current will flow, and the application circuitry will be protected.
However, if the application circuitry tries to draw its maximum rated power W , the fuse will also blow. In practice, most equipment will not draw its maximum rated power continuously- although to be safe, we typically assume that it will. Circuitos hayt capitulo 10 Documents. Circuitos hayt-capitulo Engineering. Circuitos hayt cap3 Education. Knight v. Sem5 em hayt engineering electromagnetics - 6th edition [william h.
Kemmerly / Durbin / Hayt Engineering Circuit Analysis Textbooks
Many possible solutions. Hint: Start with finding resistivity, then choose geometry. All Rights Reserved. If the DMM appears as a short, then all 5 A flows through the DMM, and none through the resistors, resulting in a false reading of 0 V for the circuit undergoing testing. The final circuit is an 8.
Analisis de circuitos en ingenieria Willian H Hayt Jr Jack E Kemmerly Steven M Durbin
solucionario análisis de circuitos en ingeniería 7ed (hayt, kemmerly)